Exercise
3.2
1. Volume of regular solids such as
cube and cuboid can be found by multiplying the dimensions. Complete the given
table by finding the volume of the given objects.
2. Complete the given table by finding
the volume of the given objects.
1. Volume = l × b × h
V =6 × 8 × 10
V = 480 cm3
2. Volume = l × b × h
900 = 3 × b × 45
b = 900 / [3 ×45] = 300/45
= 60/9 = 6.6
b = 6.6 cm
3. Volume = l × b × h
4200 =70 × 20 × h
h = 4200/ [70 × 20] = 42 / 14
h = 3cm
4. Volume = l × b × h
32000 = 80 × b × 20
b = 32000/ [80 × 20] = 320 / 16 = 36/12
b = 20cm
5. Volume = l × b × h
36 = 1 × 4 × 3
l = 36/ [4 ×3] = 36/12
l= 3 cm
3. Find the number of bricks of
dimension 20 cm × 5 cm × 10cm required to construct a wall of dimension 300 cm
× 200 cm × 20 cm.
Step: 1
Length of brick = 20cm
Breadth of brick = 5cm
Height of brick = 10cm
Volume of brick = l × b
× h
= 20 × 5 ×10
Volumr of one brick = 1000 cu.cm
Step: 2
Length of wall = 300cm
Breadth of wall = 200cm
Height of wall = 20cm
Volume of wall = l × b
× h
= 300 × 200 × 20
= 1200000 cu.cm
Volume of wall = 12,00,000 cu.cm
Volume of one brick = 1000 cu.cm
No of brick required to construct a wall = 12,00,000 + 1000 =
1200
Answer: 1200 bricks
4. How many sack of dimension 15 cm × 45
cm × 90 cm filled with rice can be kept in a room of dimension 3 m × 18 m × 9
m.
Step: 1
Length of 1 sack = 15cm
Breadth of 1 sack = 45cm
Height of 1 sack = 90cm
Volume of 1 sack = l ×
b × h
= 15 × 45 × 90
Volume of one 1 sack = 60,750 cu.cm
Step: 2
Length of a room = 3m = 300cm
Breadth of a room = 18m = 1800cm
Height of a room = 9m = 900cm
Volume of a room = l ×
b × h
= 300 × 1800 × 900
= 486000000 cu.cm
Volume of room = 48,60,00,000 cu.cm
Volume of one sack = 60,750 cu.cm
No of sack = 486000000 ÷ 60750
= 8000
Answer: Total number of
sack = 8000
Answer:
Exercise 3.2
1. (i) 90 cu.cm (ii) 3600 cu.cm (iii) 3, 75, 000 cu.cm (iv) 1000cu.cm (v) 1 cu.cm.
2. (i) 480 cu.cm (ii) 4cm (iii) 3cm (iv) 20 cm
(vi) 3m
3. 1200 bricks
4. 8000 sacks
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