Work done in volume changes
Consider a gas contained in the cylinder fitted with a movable piston. Suppose the gas is expanded quasi-statically by pushing the piston by a small distance dx as shown in Figure 8.21. Since the expansion occurs quasi-statically the pressure, temperature and internal energy will have unique values at every instant.
The small work done by the gas on the piston
The force exerted by the gas on the piston F = PA. Here A is area of the piston and P is pressure exerted by the gas on the piston.
Equation (8.14) can be rewritten as
But Adx = dV= change in volume during this expansion process.
So the small work done by the gas during the expansion is given by
Note here that is positive since the volume is increased. Here, is positive.
In general the work done by the gas by increasing the volume from Vi to Vf is given by
Suppose if the work is done on the system, then Vi > Vf . Then, W is negative.
Note here the pressure P is inside the integral in equation (8.17). It implies that while the system is doing work, the pressure need not be constant. To evaluate the integration we need to first express the pressure as a function of volume and temperature using the equation of state.
Related Topics
Privacy Policy, Terms and Conditions, DMCA Policy and Compliant
Copyright © 2018-2024 BrainKart.com; All Rights Reserved. Developed by Therithal info, Chennai.