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Chapter: 11th Mathematics : UNIT 9 : Differential Calculus Limits and Continuity

Two special Trigonometrical limits

Differential Calculus - Two special Trigonometrical limits

Two special Trigonometrical limits


Result 9.1


Proof

We use a circular sector to prove the result.

Consider the circle with centre (0, 0) and radius 1. Any point on this circle is P(cosθ, sinθ).
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11th Mathematics : UNIT 9 : Differential Calculus Limits and Continuity : Two special Trigonometrical limits |


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