Construction of tangents to a circle
Now let us discuss how to draw
(i) a tangent to a circle using its centre
(ii) a tangent to a circle using alternate segment theorem
(iii) pair of tangents from an external point
Draw a circle of radius 3 cm. Take a point P on this circle and draw a tangent at P.
Given, radius r = 3 cm
Step 1: Draw a circle with centre at O of radius 3 cm.
Step 2: Take a point P on the circle. Join OP.
Step 3: Draw perpendicular line TT’ to OP which passes through P.
Step 4: TT ‘ is the required tangent.
Draw a circle of radius 4 cm. At a point L on it draw a tangent to the circle using the alternate segment.
Given, radius=4 cm
Step 1 : With O as the centre, draw a circle of radius 4 cm.
Step 2: Take a point L on the circle. Through L draw any chord LM.
Step 3: Take a point M distinct from L and N on the circle, so that L, M and N are in anti-clockwise direction. Join LN and NM.
Step 4: Through L draw a tangent TT ’ such that ∠TLM = ∠MNL.
Step 5: TT ‘ is the required tangent.
Draw a circle of diameter 6 cm from a point P, which is 8 cm away from its centre. Draw the two tangents PA and PB to the circle and measure their lengths.
Given, diameter (d) = 6 cm, we find radius (r) = 6/2 = 3 cm
Step 1: With centre at O, draw a circle of radius 3 cm.
Step 2: Draw a line OP of length 8 cm.
Step 3: Draw a perpendicular bisector of OP, which cuts OP at M.
Step 4: With M as centre and MO as radius, draw a circle which cuts previous circle at A and B.
Step5: Join AP and BP. AP and BP are the required tangents. Thus length of the tangents are PA = PB = 7.4 cm.
Verification : In the right angle triangle OAP , PA2 = OP2 −OA2 = 64 – 9 = 55
PA = √55 = 7 4. cm (approximately) .
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